document.write( "Question 64480: looking for more help please, Thank you...
\n" ); document.write( "Given f(x) = x^2 – 8x - 20 equation (parabola), find the following:\r
\n" ); document.write( "\n" ); document.write( "21.) The vertex\r
\n" ); document.write( "\n" ); document.write( "22.) The y-intercept(s)
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Algebra.Com's Answer #47435 by rapaljer(4671)\"\" \"About 
You can put this solution on YOUR website!
The easiest way to find the vertex of f(x)= ax^2 + bx + c is \"x=-b%2F%282a%29+\"
\n" ); document.write( "In this case, \"x+=+-%28-8%29%2F%282%2A1%29+=+4\"\r
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\n" ); document.write( "\n" ); document.write( "To find the y coordinate of the vertex, \"Plug it in, plug it in!\":
\n" ); document.write( "\"y+=+x%5E2-8x-20\"
\n" ); document.write( "\"y=4%5E2+-8%2A4-20=+-36\"
\n" ); document.write( "Vertex = (4, -36)\r
\n" ); document.write( "\n" ); document.write( "Y intercept is always where x=0, so y = -20. \r
\n" ); document.write( "\n" ); document.write( "\"graph+%28300%2C600%2C+-4%2C+12%2C+-40%2C+40%2C+x%5E2+-8x-20%29+\"\r
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\n" ); document.write( "\n" ); document.write( "R^2 at SCC
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