document.write( "Question 777950: if i am going 45mph and i am a 1/2 a mile ahead of the other person, how fast would the other person be going to catch me in appr. 1 minute? And please show me the formula you use. THANKS \n" ); document.write( "
Algebra.Com's Answer #474347 by josmiceli(19441)![]() ![]() You can put this solution on YOUR website! You have head start of \n" ); document.write( "Start a stop watch when the 2nd person is \n" ); document.write( " \n" ); document.write( "Let \n" ); document.write( "when the 2nd person catches the 1st \n" ); document.write( "Let \n" ); document.write( "travels until catching the 1st person \n" ); document.write( "Let \n" ); document.write( "-------------------------- \n" ); document.write( "1st person's equation: \n" ); document.write( "(1) \n" ); document.write( "2nd person's equation: \n" ); document.write( "(2) \n" ); document.write( "------------------ \n" ); document.write( "By substitution, \n" ); document.write( " \n" ); document.write( "Multiply both sides by \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "The 2nd person must travel 75 mi/hr \n" ); document.write( "-------------- \n" ); document.write( "check: \n" ); document.write( "(2) \n" ); document.write( "(2) \n" ); document.write( "(2) \n" ); document.write( "and \n" ); document.write( "(1) \n" ); document.write( "(1) \n" ); document.write( "(1) \n" ); document.write( "(1) \n" ); document.write( "OK\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |