document.write( "Question 777950: if i am going 45mph and i am a 1/2 a mile ahead of the other person, how fast would the other person be going to catch me in appr. 1 minute? And please show me the formula you use. THANKS \n" ); document.write( "
Algebra.Com's Answer #474347 by josmiceli(19441)\"\" \"About 
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You have head start of \"+1%2F2+\" mi
\n" ); document.write( "Start a stop watch when the 2nd person is
\n" ); document.write( "\"+1%2F2+\" mi behind.
\n" ); document.write( "Let \"+1%2F60+\" = the time in hours on the stop watch
\n" ); document.write( "when the 2nd person catches the 1st
\n" ); document.write( "Let \"+d+\" = the distance in miles the 2nd person
\n" ); document.write( "travels until catching the 1st person
\n" ); document.write( "Let \"+r+\" = the rate in mi/hr of the 2nd person
\n" ); document.write( "--------------------------
\n" ); document.write( "1st person's equation:
\n" ); document.write( "(1) \"+d+-+1%2F2+=+45%2A%281%2F60%29+\"
\n" ); document.write( "2nd person's equation:
\n" ); document.write( "(2) \"+d+=+r%2A%281%2F60%29+\"
\n" ); document.write( "------------------
\n" ); document.write( "By substitution,
\n" ); document.write( "\"+r%2A%281%2F60%29+-+1%2F2+=+45%2A%281%2F60%29+\"
\n" ); document.write( "Multiply both sides by \"+60+\"
\n" ); document.write( "\"+r+-+30+=+45+\"
\n" ); document.write( "\"+r+=+75+\"
\n" ); document.write( "The 2nd person must travel 75 mi/hr
\n" ); document.write( "--------------
\n" ); document.write( "check:
\n" ); document.write( "(2) \"+d+=+r%2A%281%2F60%29+\"
\n" ); document.write( "(2) \"+d+=+75%2A%281%2F60%29+\"
\n" ); document.write( "(2) \"+d+=+1.25+\" mi
\n" ); document.write( "and
\n" ); document.write( "(1) \"+d+-+1%2F2+=+45%2A%281%2F60%29+\"
\n" ); document.write( "(1) \"+d+=+45%2F60+%2B+30%2F60+\"
\n" ); document.write( "(1) \"+d+=+75%2F60+\"
\n" ); document.write( "(1) \"+d+=+1.25+\" mi
\n" ); document.write( "OK\r
\n" ); document.write( "\n" ); document.write( "
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