document.write( "Question 777869: If x^2+y^2=10xy, prove that 2 log ( x+y/x-y)=log 3/2 \n" ); document.write( "
Algebra.Com's Answer #474295 by mananth(16946) You can put this solution on YOUR website! x^2+y^2=10xy\r \n" ); document.write( "\n" ); document.write( "x^2+2xy+y^2=10xy+2xy\r \n" ); document.write( "\n" ); document.write( "(x+y)^2= 10xy+2xy\r \n" ); document.write( "\n" ); document.write( "(x+y)^2=12xy\r \n" ); document.write( "\n" ); document.write( "x^2+y^2=10xy\r \n" ); document.write( "\n" ); document.write( "x^2-2xy+y^2=10xy-2xy\r \n" ); document.write( "\n" ); document.write( "(x-y)^2=8xy\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2 log ( x+y/x-y)=log 3/2\r \n" ); document.write( "\n" ); document.write( "LHS \n" ); document.write( "2 log ( x+y/x-y)\r \n" ); document.write( "\n" ); document.write( "log((x+y)/(x-y))^2\r \n" ); document.write( "\n" ); document.write( "=log((x+y)^2/(x-y)^2)\r \n" ); document.write( "\n" ); document.write( "=log (12xy/8xy)\r \n" ); document.write( "\n" ); document.write( "= log3/2=RHS \n" ); document.write( " |