document.write( "Question 777830:  in triangle ABC angle A minus angle B is 15 degree angle B minus C is 30 degrees
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document.write( "find A and B \n" );
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| Algebra.Com's Answer #474293 by negative49(13)     You can put this solution on YOUR website! sum of interior angles of triangle: \n" ); document.write( "A° + B° + C° = 180°\r \n" ); document.write( "\n" ); document.write( "I represent A° and C° as variable B \n" ); document.write( "A-B = 15 \n" ); document.write( "A= 15 + B\r \n" ); document.write( "\n" ); document.write( "B-C = 30 \n" ); document.write( "C = -30 + B\r \n" ); document.write( "\n" ); document.write( "(15 + B) + (B) + (-30 + B) = 180 \n" ); document.write( "-15 + 3B = 180 \n" ); document.write( "3B = 195 \n" ); document.write( "B° = 65\r \n" ); document.write( "\n" ); document.write( "A- (65) = 15 \n" ); document.write( "A = 15 + 65 \n" ); document.write( "A° = 80\r \n" ); document.write( "\n" ); document.write( "A° = 80 B° = 65 \n" ); document.write( "Proof: \n" ); document.write( "B-C= 30 \n" ); document.write( "C = -30 + B \n" ); document.write( "C = -30 + 65 \n" ); document.write( "C°= 35\r \n" ); document.write( "\n" ); document.write( "A° + B° + C° = 180° \n" ); document.write( "80° + 65° + 35° = 180° \n" ); document.write( " \n" ); document.write( " |