document.write( "Question 777742: John drove to Dayton in 5 hours, on the way back there was less traffic so he made it in 3 hours, If John averaged 26mph faster on the return trip, how fast did he drive each way? \n" ); document.write( "
Algebra.Com's Answer #474286 by lwsshak3(11628)\"\" \"About 
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John drove to Dayton in 5 hours, on the way back there was less traffic so he made it in 3 hours, If John averaged 26mph faster on the return trip, how fast did he drive each way?
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\n" ); document.write( "let x=driving speed to dayton
\n" ); document.write( "x+26=driving speed on return trip
\n" ); document.write( "distance=speed*travel time
\n" ); document.write( "..
\n" ); document.write( "5x=3(x+26)
\n" ); document.write( "5x=3x+78
\n" ); document.write( "2x=78
\n" ); document.write( "x=39
\n" ); document.write( "x+26=65
\n" ); document.write( "driving speed to dayton=39 mph
\n" ); document.write( "driving speed on return trip=65 mph
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