document.write( "Question 777742: John drove to Dayton in 5 hours, on the way back there was less traffic so he made it in 3 hours, If John averaged 26mph faster on the return trip, how fast did he drive each way? \n" ); document.write( "
Algebra.Com's Answer #474286 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! John drove to Dayton in 5 hours, on the way back there was less traffic so he made it in 3 hours, If John averaged 26mph faster on the return trip, how fast did he drive each way? \n" ); document.write( "*** \n" ); document.write( "let x=driving speed to dayton \n" ); document.write( "x+26=driving speed on return trip \n" ); document.write( "distance=speed*travel time \n" ); document.write( ".. \n" ); document.write( "5x=3(x+26) \n" ); document.write( "5x=3x+78 \n" ); document.write( "2x=78 \n" ); document.write( "x=39 \n" ); document.write( "x+26=65 \n" ); document.write( "driving speed to dayton=39 mph \n" ); document.write( "driving speed on return trip=65 mph \n" ); document.write( " |