document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=777786>Question 777786</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how many gallons of 5% alcohol solution must be mixed with 90 gallons of 1% solution to obtain a 2% solution<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #474259 by </B><A HREF=/tutors/aboutme.mpl?userid=dkppathak><B>dkppathak(439)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=dkppathak><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=dkppathak><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=474259\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let x gallon 5%  solution  added in 90 gallon of 1% solutions <BR>\n" );
document.write( "alcohol available in 5 %  solution =5x/100<BR>\n" );
document.write( "alcohol available in 1% 90 gallon =90/100 gallon <BR>\n" );
document.write( "after mixing alcohol available  in 2% solution=(90+x)2/100<BR>\n" );
document.write( "as per given conditions <BR>\n" );
document.write( "5x/100+90/100=2(90+x)/100<BR>\n" );
document.write( "5x+90=180+2x<BR>\n" );
document.write( "5x-2x=180-90<BR>\n" );
document.write( "3x=90<BR>\n" );
document.write( "x=90/3<BR>\n" );
document.write( "x=30 gallon<BR>\n" );
document.write( "answer 30 gallon of 5% alcohol is to be added in 90 gallon 1% solution to get 2%alcohol solution<BR>\n" );
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