document.write( "Question 64622: Solve, and express you answer in exact form: log(x) + ln(x) = 1 \n" ); document.write( "
Algebra.Com's Answer #47422 by rapaljer(4671)\"\" \"About 
You can put this solution on YOUR website!
The first step is to get everything into the same base logarithm, by using the formula \"log+%2810%2Cx%29+=+%28ln+x%29%2F%28ln+10%29+\".\r
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\n" ); document.write( "\n" ); document.write( "log(x) + ln(x) = 1
\n" ); document.write( "\"%28ln+x%29%2F%28ln+10%29+%2Bln+x+=+1+\".\r
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\n" ); document.write( "\n" ); document.write( "You might want to clear the fraction by multiplying both sides times ln 10:
\n" ); document.write( "\"ln+x+%2B+%28ln+10%29%2A%28ln+x%29+=+ln+10\"\r
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\n" ); document.write( "\n" ); document.write( "Next, factor the ln x, which is a common factor on the left side:
\n" ); document.write( "\"%28ln+x%29+%2A%281+%2B+ln+10%29+=+ln+10\"\r
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\n" ); document.write( "\n" ); document.write( "Divide both sides by (1 + ln 10)\r
\n" ); document.write( "\n" ); document.write( "\"ln+x+=+%28ln+10%29%2F%281%2B+ln+10%29+\"\r
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\n" ); document.write( "\n" ); document.write( "Raise both sides as a power of e:\r
\n" ); document.write( "\n" ); document.write( "\"x+=+e%5E%28%28ln+10%29%2F%281%2B+ln+10%29%29+\"\r
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\n" ); document.write( "\n" ); document.write( "R^2 at SCC \r
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\n" ); document.write( "\n" ); document.write( "P.S. Nice problem!!!
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