document.write( "Question 777658: Beth had planned to run an average of 6 miles per hour in a race. She had a very good race and actually ran at an average speed of 7 miles per hour, finishing 10 minutes sooner than she would have if she had averaged 6 miles per hour. How long was the race? \n" ); document.write( "
Algebra.Com's Answer #474216 by mananth(16946)\"\" \"About 
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Beth had planned to run an average of 6 miles per hour in a race. She had a very good race and actually ran at an average speed of 7 miles per hour, finishing 10 minutes sooner than she would have if she had averaged 6 miles per hour. How long was the race?\r
\n" ); document.write( "\n" ); document.write( "time taken with speed of 6 mph - time taken with speed of 7 mph =10minutes\r
\n" ); document.write( "\n" ); document.write( "t=d/r\r
\n" ); document.write( "\n" ); document.write( "let x be the distance of the race
\n" ); document.write( "time = x/6 ( planned)\r
\n" ); document.write( "\n" ); document.write( "(x/7) = actual time\r
\n" ); document.write( "\n" ); document.write( "\"x%2F6-x%2F7=10%2F60\"\r
\n" ); document.write( "\n" ); document.write( "\"x%2F6-x%2F7+=+1%2F6\"\r
\n" ); document.write( "\n" ); document.write( "Multiply equation by 42\r
\n" ); document.write( "\n" ); document.write( "\"%28x%2A42%29%2F6+-%28x%2A42%29%2F7+=42%2F6\"\r
\n" ); document.write( "\n" ); document.write( "\"7x-6x=7\"\r
\n" ); document.write( "\n" ); document.write( "x=7=> distance\r
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