document.write( "Question 777658: Beth had planned to run an average of 6 miles per hour in a race. She had a very good race and actually ran at an average speed of 7 miles per hour, finishing 10 minutes sooner than she would have if she had averaged 6 miles per hour. How long was the race? \n" ); document.write( "
Algebra.Com's Answer #474216 by mananth(16946)![]() ![]() You can put this solution on YOUR website! Beth had planned to run an average of 6 miles per hour in a race. She had a very good race and actually ran at an average speed of 7 miles per hour, finishing 10 minutes sooner than she would have if she had averaged 6 miles per hour. How long was the race?\r \n" ); document.write( "\n" ); document.write( "time taken with speed of 6 mph - time taken with speed of 7 mph =10minutes\r \n" ); document.write( "\n" ); document.write( "t=d/r\r \n" ); document.write( "\n" ); document.write( "let x be the distance of the race \n" ); document.write( "time = x/6 ( planned)\r \n" ); document.write( "\n" ); document.write( "(x/7) = actual time\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Multiply equation by 42\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x=7=> distance\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |