document.write( "Question 777596: Find an equation of the line that passes through the given point and is perpendicular to the given line. Write the equation in slope-intercept form.
\n" ); document.write( "(8, −2), 7x = 9y − 8
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Algebra.Com's Answer #474187 by MathLover1(20849)\"\" \"About 
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passes through the given point (8,-2)\r
\n" ); document.write( "\n" ); document.write( "and is perpendicular to the given line \"7x+=+9y-+8\"\r
\n" ); document.write( "\n" ); document.write( " the equation in slope-intercept form:\r
\n" ); document.write( "\n" ); document.write( "\"7x%2B8+=+9y+\"\r
\n" ); document.write( "\n" ); document.write( "\"y=%287%2F9%29x%2B8%2F9++\"\r
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Solved by pluggable solver: Finding the Equation of a Line Parallel or Perpendicular to a Given Line

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\n" ); document.write( " Remember, any two perpendicular lines are negative reciprocals of each other. So if you're given the slope of \"7%2F9\", you can find the perpendicular slope by this formula:
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\n" ); document.write( " \"m%5Bp%5D=-1%2Fm\" where \"m%5Bp%5D\" is the perpendicular slope
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\n" ); document.write( " \"m%5Bp%5D=-1%2F%287%2F9%29\" So plug in the given slope to find the perpendicular slope
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\n" ); document.write( " \"m%5Bp%5D=%28-1%2F1%29%289%2F7%29\" When you divide fractions, you multiply the first fraction (which is really \"1%2F1\") by the reciprocal of the second
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\n" ); document.write( " \"m%5Bp%5D=-9%2F7\" Multiply the fractions.
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\n" ); document.write( " So the perpendicular slope is \"-9%2F7\"
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\n" ); document.write( " So now we know the slope of the unknown line is \"-9%2F7\" (its the negative reciprocal of \"7%2F9\" from the line \"y=%287%2F9%29%2Ax%2B8%2F9\").\n" ); document.write( "Also since the unknown line goes through (8,-2), we can find the equation by plugging in this info into the point-slope formula
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\n" ); document.write( " Point-Slope Formula:
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\n" ); document.write( " \"y-y%5B1%5D=m%28x-x%5B1%5D%29\" where m is the slope and (\"x%5B1%5D\",\"y%5B1%5D\") is the given point
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\n" ); document.write( " \"y%2B2=%28-9%2F7%29%2A%28x-8%29\" Plug in \"m=-9%2F7\", \"x%5B1%5D=8\", and \"y%5B1%5D=-2\"
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\n" ); document.write( " \"y%2B2=%28-9%2F7%29%2Ax%2B%289%2F7%29%288%29\" Distribute \"-9%2F7\"
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\n" ); document.write( " \"y%2B2=%28-9%2F7%29%2Ax%2B72%2F7\" Multiply
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\n" ); document.write( " \"y=%28-9%2F7%29%2Ax%2B72%2F7-2\"Subtract \"-2\" from both sides to isolate y
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\n" ); document.write( " \"y=%28-9%2F7%29%2Ax%2B72%2F7-14%2F7\" Make into equivalent fractions with equal denominators
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\n" ); document.write( " \"y=%28-9%2F7%29%2Ax%2B58%2F7\" Combine the fractions
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\n" ); document.write( " \"y=%28-9%2F7%29%2Ax%2B58%2F7\" Reduce any fractions
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\n" ); document.write( " So the equation of the line that is perpendicular to \"y=%287%2F9%29%2Ax%2B8%2F9\" and goes through (\"8\",\"-2\") is \"y=%28-9%2F7%29%2Ax%2B58%2F7\"
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\n" ); document.write( " So here are the graphs of the equations \"y=%287%2F9%29%2Ax%2B8%2F9\" and \"y=%28-9%2F7%29%2Ax%2B58%2F7\"
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\n" ); document.write( " graph of the given equation \"y=%287%2F9%29%2Ax%2B8%2F9\" (red) and graph of the line \"y=%28-9%2F7%29%2Ax%2B58%2F7\"(green) that is perpendicular to the given graph and goes through (\"8\",\"-2\")
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