document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=777594>Question 777594</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A certain recipe asks for 5/7 cup of granola. How much is needed to make 3/2 of a recipe. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #474183 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=474183\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A certain recipe asks for 5/7 cup of granola. <BR>\n" );
document.write( "How much is needed to make 3/2 of a recipe.<BR>\n" );
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document.write( "Use a proportion::<BR>\n" );
document.write( "x/(3/2) = (5/7)/1<BR>\n" );
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document.write( "x = (3/2)(5/7)<BR>\n" );
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document.write( "x = 15/14<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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