document.write( "Question 777495: kali left school and traveled toward her friend's house at an average speed of 40 km/h. matt left one hour later and traveled in the opposite direction with an average speed of 50 km/h. how many hours does matt needs to travel before they are 400 km apart?
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Algebra.Com's Answer #474132 by hope723(1)\"\" \"About 
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Kali r: 40 t:x+1
\n" ); document.write( "Matt r: 50 t:x\r
\n" ); document.write( "\n" ); document.write( "Okay. First what you're going to do is write your equation, d=rt
\n" ); document.write( "Because distance is 400, plug that in. Also, because you have two people, the equation is d=rt+rt, if that makes any sense at all. So here's your equation.\r
\n" ); document.write( "\n" ); document.write( "\"400=40%28x%2B1%29%2B50x\"
\n" ); document.write( "Now use the distributive property.
\n" ); document.write( "\"400=40x%2B40%2B50x\"
\n" ); document.write( "Now, subtract 40 from both sides of the equal sign.
\n" ); document.write( "\"360=40x%2B50x\"
\n" ); document.write( "Combine like terms.
\n" ); document.write( "\"360=90x\"
\n" ); document.write( "Now, divide both sides by 90.
\n" ); document.write( "\"4=x\"
\n" ); document.write( "Therefore, Matt needs to drive four hours before him and Kali are 400 km apart.
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