document.write( "Question 777365: The radioactive element americium-241 has a half-life of 432 years. Suppose we start with a 20-g mass of americium-241.
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document.write( "How much will be left after 321 years? Compute the answer to three significant digits. \n" );
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Algebra.Com's Answer #474068 by Cromlix(4381)![]() ![]() You can put this solution on YOUR website! 321/432 * 100 = 74.3% \n" ); document.write( "74.3% of 20g of americium - 241 \n" ); document.write( "= 14.86g \n" ); document.write( "20g - 14.86g = 5.14g left active. \n" ); document.write( "Hope this helps. \n" ); document.write( ";-) \n" ); document.write( " |