document.write( "Question 777365: The radioactive element americium-241 has a half-life of 432 years. Suppose we start with a 20-g mass of americium-241.
\n" ); document.write( "How much will be left after 321 years? Compute the answer to three significant digits.
\n" ); document.write( "

Algebra.Com's Answer #474068 by Cromlix(4381)\"\" \"About 
You can put this solution on YOUR website!
321/432 * 100 = 74.3%
\n" ); document.write( "74.3% of 20g of americium - 241
\n" ); document.write( "= 14.86g
\n" ); document.write( "20g - 14.86g = 5.14g left active.
\n" ); document.write( "Hope this helps.
\n" ); document.write( ";-)
\n" ); document.write( "
\n" );