document.write( "Question 777397: I have a system of two linear equations in the form ax+by=c. I am trying to convert them to the form y=ax+b for graphing. System:\r
\n" ); document.write( "\n" ); document.write( "2/x - 3/y = 4
\n" ); document.write( "1/x + 4/y = -10
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\n" ); document.write( "I have tried: \r
\n" ); document.write( "\n" ); document.write( "2/x - 3/y = 4 ......................-3/y = -2/x +4....................1/y=2/3x - 1 1/3
\n" ); document.write( "- 2/x.......- 2/x....................x -1/3....x -1/3
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\n" ); document.write( "Also tried;\r
\n" ); document.write( "\n" ); document.write( "2/x - 3/y = 4 __________________ -3/y = -2/x + 4 ________________-3 = -2/x x y +4
\n" ); document.write( "- 2/x ___- 2/x _________________ x y ________x y \r
\n" ); document.write( "\n" ); document.write( "I did these processes on the 1/x + 4/y = -10, too. I am stuck on the fractions with the variable in the denominator, i do not know how to handle them. \r
\n" ); document.write( "\n" ); document.write( " -Alexandrea
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Algebra.Com's Answer #474052 by Alan3354(69443)\"\" \"About 
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I have a system of two linear equations in the form ax+by=c. I am trying to convert them to the form y=ax+b for graphing. System:\r
\n" ); document.write( "\n" ); document.write( "2/x - 3/y = 4
\n" ); document.write( "1/x + 4/y = -10
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\n" ); document.write( "Those are not linear equations.
\n" ); document.write( "The graph of each is a hyperbola.
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\n" ); document.write( "You can solve for y in order to make a table of points to graph them.
\n" ); document.write( "2/x - 3/y = 4
\n" ); document.write( "2y/x - 3 = 4y
\n" ); document.write( "2y/x - 4y = 3
\n" ); document.write( "y*(2/x - 4) = 3
\n" ); document.write( "y = 3/(2/x - 4)
\n" ); document.write( "y = 3/(2/x - 4x/x) = 3/((2-4x)/x)
\n" ); document.write( "y = 3x/(2-4x)
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\n" ); document.write( "dl the FREE graph software at\r
\n" ); document.write( "\n" ); document.write( "http://www.padowan.dk\r
\n" ); document.write( "\n" ); document.write( "Use F6 to enter the equations as they are.\r
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