document.write( "Question 66751This question is from textbook College Algebra
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document.write( ": A rectangular piece of sheet metal with an area of 1200 in^2 is to be bent into a cylindrical length of stovepipe having a volume of 600 in^3. What are the dimensions of the sheet metal?
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document.write( "I am to come up with a system of equations to solve this problem. The sides of the rectangle are labeled x and y.
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document.write( "I know that {x*y=1200 in^2}; x would be the circumference of the cylinder which would mean that {x=2(PI)r}; the volume would be {(PI)r^2(y)=600 in^3}. I just can't figure out how to show it all in terms of y and x to figure out the equation. Thanks.\r
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Algebra.Com's Answer #47403 by Earlsdon(6294)![]() ![]() ![]() You can put this solution on YOUR website! You are correct in what you have done so far. \n" ); document.write( "Let's start with the volume of the cylindical pipe. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The dimensions of the rectangular metal sheet are: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |