document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=777140>Question 777140</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many hours will it take a car traveling at 60 mph to catch up to a car traveling at 40 mph if the slower car starts one hour before the faster car? And please show the work so i can understand it </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #473936 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=473936\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> How many hours will it take a car traveling at 60 mph to catch up to a car traveling at 40 mph if the slower car starts one hour before the faster car? And please show the work so i can understand it<BR>\n" );
document.write( "Car I speed = 40 mph\r<BR>\n" );
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document.write( "Car II speed = 60 mph\r<BR>\n" );
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document.write( "Before Car II starts Car I has traveled 40 miles in 1 hour.\r<BR>\n" );
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document.write( "Since they are traveling in same direction effective speed = 60-40 mph<BR>\n" );
document.write( "=20 mph\r<BR>\n" );
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document.write( "Catch up speed = 20 mph<BR>\n" );
document.write( "catch up distance = 40 miles\r<BR>\n" );
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document.write( "time to catch up = 40/20 = 2 hours </SPAN>\n" );
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