document.write( "Question 777055: The length of a rectangle is 3 in. more than its width. If the length were decreased by 2 in. and the width were increased by 1 in., the perimeter of the resulting rectangle would be 24 in. Find the dimensions of the original rectangle.
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Algebra.Com's Answer #473902 by lwsshak3(11628)\"\" \"About 
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The length of a rectangle is 3 in. more than its width. If the length were decreased by 2 in. and the width were increased by 1 in., the perimeter of the resulting rectangle would be 24 in. Find the dimensions of the original rectangle.
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\n" ); document.write( "let x=width of original rectangle
\n" ); document.write( "x+3=length of original rectangle
\n" ); document.write( "..
\n" ); document.write( "x+3-2=x+1 ( length decreased by 2 in)
\n" ); document.write( "x+1 (width increased by 1 in)
\n" ); document.write( "perimeter=twice the width+twice the length
\n" ); document.write( "2(x+1)+2(x+1)=24
\n" ); document.write( "2x+2+2x+2=24
\n" ); document.write( "4x=20
\n" ); document.write( "x=5
\n" ); document.write( "x+3=8
\n" ); document.write( "width of original rectangle=5 in
\n" ); document.write( "length of original rectangle=8 in
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