document.write( "Question 777055: The length of a rectangle is 3 in. more than its width. If the length were decreased by 2 in. and the width were increased by 1 in., the perimeter of the resulting rectangle would be 24 in. Find the dimensions of the original rectangle.
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Algebra.Com's Answer #473902 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! The length of a rectangle is 3 in. more than its width. If the length were decreased by 2 in. and the width were increased by 1 in., the perimeter of the resulting rectangle would be 24 in. Find the dimensions of the original rectangle. \n" ); document.write( "*** \n" ); document.write( "let x=width of original rectangle \n" ); document.write( "x+3=length of original rectangle \n" ); document.write( ".. \n" ); document.write( "x+3-2=x+1 ( length decreased by 2 in) \n" ); document.write( "x+1 (width increased by 1 in) \n" ); document.write( "perimeter=twice the width+twice the length \n" ); document.write( "2(x+1)+2(x+1)=24 \n" ); document.write( "2x+2+2x+2=24 \n" ); document.write( "4x=20 \n" ); document.write( "x=5 \n" ); document.write( "x+3=8 \n" ); document.write( "width of original rectangle=5 in \n" ); document.write( "length of original rectangle=8 in \n" ); document.write( " |