document.write( "Question 776966: can you show me step by step on how to solve this : |x-3|= 2x \n" ); document.write( "
Algebra.Com's Answer #473864 by MathTherapy(10552)\"\" \"About 
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\n" ); document.write( "can you show me step by step on how to solve this : |x-3|= 2x\r
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\n" ); document.write( "\n" ); document.write( "|x - 3| = 2x\r
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\n" ); document.write( "\n" ); document.write( "Either x - 3 = 2x__________________OR__________________x - 3 = - 2x \r
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\n" ); document.write( "\n" ); document.write( "Either x - 2x = 3__________________OR__________________x + 2x = 3 \r
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\n" ); document.write( "\n" ); document.write( "Either - x = 3____________________OR__________________3x = 3 \r
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\n" ); document.write( "\n" ); document.write( "Either x = - 3_____________________OR__________________x = \"3%2F3\", or 1\r
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\n" ); document.write( "\n" ); document.write( "Checking by substituting - 3, we find that - 3 is an EXTRANEOUS solution as \"6+%3C%3E+-+6\"\r
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\n" ); document.write( "\n" ); document.write( "Substituting 1 in the original absolute-value equation though yields a true statement. Therefore, \"highlight_green%28x+=+1%29\"\r
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\n" ); document.write( "\n" ); document.write( "You can do the check!! \r
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\n" ); document.write( "\n" ); document.write( "Further help is available, online or in-person, for a fee, obviously. Send comments, “thank-yous,” and inquiries to “D” at MathMadEzy@aol.com
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