document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=776945>Question 776945</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A collection of 40 dimes and quarters has a value of $6.40. How many of each coin type are in the collection? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #473824 by </B><A HREF=/tutors/aboutme.mpl?userid=FrankM><B>FrankM(1040)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=FrankM><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=FrankM><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=473824\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 10D + 25Q = 640 (you see that a dime is 10 cents, and quarter, 25 cents)<BR>\n" );
document.write( "D + Q = 40 (there are 40 coins) \r<BR>\n" );
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document.write( "Multiply both sides of second equation by -10 to get\r<BR>\n" );
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document.write( "-10D - 10Q = -400 and add to first equation \r<BR>\n" );
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document.write( "0D + 15Q = 240\r<BR>\n" );
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document.write( "Q = 16<BR>\n" );
document.write( "D = 40-16 = 24\r<BR>\n" );
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document.write( "16 quarters are $4.00<BR>\n" );
document.write( "24 dimes are  $2.40\r<BR>\n" );
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document.write( "$6.40 total  </SPAN>\n" );
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