document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=776923>Question 776923</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two parallel chord lies on opposite sides of the centre of a circle of diameter 24cm.the length of the chords are 5cm and 6cm. Calculate the distance between the two chords? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #473819 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39618)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=473819\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> One way to handle this is lay the circle onto a cartesian system, centered at the origin, radius of the circle 12 cm.  Examine the two chords separately.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E2%2By%5E2=12%5E2 ALIGN=MIDDLE  ALT=\"x%5E2%2By%5E2=12%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y%5E2=12%5E2-x%5E2 ALIGN=MIDDLE  ALT=\"y%5E2=12%5E2-x%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight%28y=sqrt%2812%5E2-x%5E2%29%29 ALIGN=MIDDLE  ALT=\"highlight%28y=sqrt%2812%5E2-x%5E2%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "The two lengths for x to examine for y are HALF of 5 cm, and HALF of 6 cm.  Evaluate for each, separately, and then SUM the two results for y.  This result is the distance between the two chords.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+drawing%28+300%2C+300%2C+%0D%0A++++++++++-15%2C+15%2C%0D%0A++++++++++-15%2C+15%2C%0D%0A++++++++++circle%28+0%2C+0%2C+12+%29%2C%0D%0A++++++++++circle%280%2C0%2C0.2%29%2C%0D%0A++++++++++line%28-2.5%2C11.4%2C2.5%2C11.4%29%2C%0D%0A++++++++++locate%28+0%2C+0%2C+O+%29%2C%0D%0A++++++++++blue%28locate%282.5%2C0%2C2.5%29%29%2C%0D%0A++++++++++blue%28circle%282.5%2C0%2C0.2%29%29%2C%0D%0A++++++++++green%28line%28-11.9%2C0%2C11.9%2C0%29%29%0D%0A+%29 ALIGN=MIDDLE   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "This picture shows x=2.5, corresponding to a chord length of 5 cm.  The equation for the circle is shown in the symbolic description already described.  The value for y is the distance of the chord from the diameter.  The diameter here is shown as the horizontal axis from -12 to +12.  The distance is computed as <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y=sqrt%28144-2.5%5E2%29 ALIGN=MIDDLE  ALT=\"y=sqrt%28144-2.5%5E2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >.<BR>\n" );
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document.write( "A similar picture and process is done for the 6 cm. chord. </SPAN>\n" );
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