document.write( "Question 776905: Let the daughter's age be x
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document.write( "Let the father's age be 4x
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document.write( "3 years ago: Daughter's age = x-3
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document.write( "Father's age = 4x-3
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document.write( "Product of their ages:( x-3)(4x-3)=430
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document.write( "Opening the bracket and applying quadratic formula method, we shall have the roots as x= 12.3 and -8.6
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document.write( "So, taking the positive value of x= 12.3years.
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document.write( "Present ages:
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document.write( "Daughter's (x-3)years = 12.3-3 =9.30years (9 years 3 months)
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document.write( "Father's age: (4x-3)years= 4×12.3-3 = 46.21years (46 years 2 months 1day)\r
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document.write( "Checking:
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document.write( "9.30×46.21= 429.753 = 430 (approximated) \n" );
document.write( "
Algebra.Com's Answer #473809 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! 3 years ago a father was 4 times as old as his daughter is now. The product of their ages is 430. Calculate their present ages. \n" ); document.write( "--------------- \n" ); document.write( "F*D = 430 \n" ); document.write( "F-3 = 4(D-3) \n" ); document.write( "F = 4D - 9 \n" ); document.write( "---- \n" ); document.write( "D*(4D-9) = 430 \n" ); document.write( "4D^2 - 9D - 430 = 0 \n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "---------------------- \n" ); document.write( "D = x \n" ); document.write( "---- \n" ); document.write( "Not an integer solution. \n" ); document.write( " \n" ); document.write( " |