document.write( "Question 776905: Let the daughter's age be x
\n" );
document.write( "Let the father's age be 4x
\n" );
document.write( "3 years ago: Daughter's age = x-3
\n" );
document.write( "Father's age = 4x-3
\n" );
document.write( "Product of their ages:( x-3)(4x-3)=430
\n" );
document.write( "Opening the bracket and applying quadratic formula method, we shall have the roots as x= 12.3 and -8.6
\n" );
document.write( "So, taking the positive value of x= 12.3years.
\n" );
document.write( "Present ages:
\n" );
document.write( "Daughter's (x-3)years = 12.3-3 =9.30years (9 years 3 months)
\n" );
document.write( "Father's age: (4x-3)years= 4×12.3-3 = 46.21years (46 years 2 months 1day)\r
\n" );
document.write( "\n" );
document.write( "Checking:
\n" );
document.write( "9.30×46.21= 429.753 = 430 (approximated) \n" );
document.write( "
Algebra.Com's Answer #473801 by MathTherapy(10552)![]() ![]() You can put this solution on YOUR website! 3 years ago a father was 4 times as old as his daughter is now. The product of their ages is 430. Calculate their present ages.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Let daughter's, and father's current ages be D, and F, respectively\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Then: F - 3 = 4D ----- F = 4D + 3 ----- eq (i)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Also FD = 430 ------ eq (ii)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "D(4D + 3) = 430 ----- Substituting \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Solve this to get daughter's age. Then find father's: \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "You should get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Daughter's current age: \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Father's current age: \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "You can do the check!! \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Further help is available, online or in-person, for a fee, obviously. Send comments, “thank-yous,” and inquiries to “D” at MathMadEzy@aol.com \n" ); document.write( " |