document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=776781>Question 776781</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A train leaves Philadelphia at 5:00 P.M. A second train leaves the same city in the same direction at 8:00 P.M. The second train travels 75mph faster that the first. If the second train overtakes the first at 10:00 P.M., what is the speed of the two trains. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #473720 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=473720\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A train leaves Philadelphia at 5:00 P.M. A second train leaves the same city in the same direction at 8:00 P.M. The second train travels 75mph faster that the first. If the second train overtakes the first at 10:00 P.M., what is the speed of the two trains.<BR>\n" );
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document.write( "2nd train DATA:<BR>\n" );
document.write( "time = 2 hrs ; rate = x + 75 mph ; distance = 2(x+75) = 2x+150 miles<BR>\n" );
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document.write( "1st train DATA:<BR>\n" );
document.write( "time = 5 hrs ; rate ; x mph ; distance = 5x miles<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "distance = distance<BR>\n" );
document.write( "5x = 2x+150<BR>\n" );
document.write( "3x = 150<BR>\n" );
document.write( "x = 50 mph (speed of the 1st train)<BR>\n" );
document.write( "x+75 = 125 mph (speed of the 2nd train)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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document.write( " </SPAN>\n" );
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