document.write( "Question 776770: Jack is twice as old as Jill. In 2 years, Jack will be 4 times as old as Jill was 9 years ago. How old are they now \n" ); document.write( "
Algebra.Com's Answer #473709 by ramkikk66(644)\"\" \"About 
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document.write( "Jack is twice as old as Jill. In 2 years, Jack will be 4 times as old as Jill was 9 years ago. How old are they now\r\n" );
document.write( "Ans:\r\n" );
document.write( "Let Jill's age be x.\r\n" );
document.write( "Then Jack's age is 2*x\r\n" );
document.write( "In 2 years, Jack's age will be = 2*x + 2\r\n" );
document.write( "Jill's age 9 years ago = x - 9\r\n" );
document.write( "So we have the equation\r\n" );
document.write( "\"2%2Ax+%2B+2+=+4%2A%28x+-+9%29\"\r\n" );
document.write( "\"2%2Ax+%2B+2+=+4%2Ax+-+36\"\r\n" );
document.write( "simplifying\r\n" );
document.write( "\"2%2Ax+=+38\"\r\n" );
document.write( "\"x+=+19\"\r\n" );
document.write( "Jill's age = 19 and Jack's age = 38\r\n" );
document.write( "Check: 2 years later, Jack will be 40. Jill's age 9 years ago = 10. 40 = 4*10.\r\n" );
document.write( "Correct :)\r\n" );
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