document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=776691>Question 776691</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hello,\r<BR>\n" );
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document.write( "I need help getting started with this word problem.  I already know the answer; Darwin has 36 nickels, 18 dimes, and 11 quarters. I just want to figure out how.\r<BR>\n" );
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document.write( "Darin has just emptied his piggy bank filled with nickels, dimes, and quarters worth $6.35. If there are seven more dimes than quarters, and twice as many nickels as dimes, how many of each type of coin does he have?\r<BR>\n" );
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document.write( "x=Quarters<BR>\n" );
document.write( "2x=Nickels<BR>\n" );
document.write( "x+7=Dimes\r<BR>\n" );
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document.write( "So...assuming the above is correct, is it 2x+x+7=6.35?  After that I did .25(x)=.25x<BR>\n" );
document.write( ".05(2x)=.1x<BR>\n" );
document.write( ".1(x+7)=.1+.7\r<BR>\n" );
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document.write( ".25x+.1x+.1x+.7=6.35<BR>\n" );
document.write( "I tried solving it and got 12.555, and that does not seem right.  Please help, what did I do wrong?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #473677 by </B><A HREF=/tutors/aboutme.mpl?userid=fcabanski><B>fcabanski(1391)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fcabanski><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=473677\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You have it written as twice as many nickles as quarters.  Quarters is x.  You have nickles as 2x.  That's not correct.<P><BR>\n" );
document.write( "The problem indicates there are twice as many nickels as dimes.  There are x+7 dimes, so there are 2(x+7) nickels.<P><BR>\n" );
document.write( "Solve it from there. </SPAN>\n" );
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