document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=776678>Question 776678</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a small square is constructed. Then increasing each side by 2 meters makes a new square. The perimeter of the new square is 3 meters shorter than five times the length of one side of the original square. Fine the dimensions of the original square.\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #473669 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=473669\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a small square is constructed. Then increasing each side by 2 meters makes a new square. The perimeter of the new square is 3 meters shorter than five times the length of one side of the original square. Fine the dimensions of the original square.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "let side length =x\r<BR>\n" );
document.write( "\n" );
document.write( "then perimeter = 4x\r<BR>\n" );
document.write( "\n" );
document.write( "side increased by 2\r<BR>\n" );
document.write( "\n" );
document.write( "side = (x+2)\r<BR>\n" );
document.write( "\n" );
document.write( "New perimeter = 4(x+2)\r<BR>\n" );
document.write( "\n" );
document.write( "4(x+2)=5x-3\r<BR>\n" );
document.write( "\n" );
document.write( "4x+8=5x-3\r<BR>\n" );
document.write( "\n" );
document.write( "5x-4x=11<BR>\n" );
document.write( "x=11\r<BR>\n" );
document.write( "\n" );
document.write( "side = 11 m </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );