document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=776325>Question 776325</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve the linear equation given the following:<BR>\n" );
document.write( "Perpendicular to 2x-12y=4 and passing through the point (-1/2,1) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #473505 by </B><A HREF=/tutors/aboutme.mpl?userid=Cromlix><B>Cromlix(4381)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Cromlix><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Cromlix><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=473505\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Reaarange 2x - 12y = 4 into<BR>\n" );
document.write( "y = mx + c form<BR>\n" );
document.write( "y = 1/6x - 1/3<BR>\n" );
document.write( "Lines that are perpendicular to<BR>\n" );
document.write( "one another have slopes (m) that<BR>\n" );
document.write( "multiply together to give - 1<BR>\n" );
document.write( "m1 * m2 = -1<BR>\n" );
document.write( "Above equation has a slope of 1/6<BR>\n" );
document.write( "1/6 * m2 = -1<BR>\n" );
document.write( "      m2 = -6<BR>\n" );
document.write( "Using the equation<BR>\n" );
document.write( "y - b = m(x - a) with (-1/2, 1)<BR>\n" );
document.write( "a = -1/2, b = 1 and m = -6<BR>\n" );
document.write( "y - 1 = -6(x - (-1/2))<BR>\n" );
document.write( "y - 1 = -6x - 3<BR>\n" );
document.write( "y = -6x - 3 + 1<BR>\n" );
document.write( "y = -6x - 2<BR>\n" );
document.write( "Hope this helps.<BR>\n" );
document.write( ":-) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );