document.write( "Question 776320: The present ages of a man and his son amount to 55 years.10 years ago,the man was 6 times as old as his son.find the present ages \n" ); document.write( "
Algebra.Com's Answer #473502 by Cromlix(4381)![]() ![]() You can put this solution on YOUR website! The present ages of a man and his son amount to 55 years. \n" ); document.write( "M + S = 55 \n" ); document.write( "M = 55 - S \n" ); document.write( "10 years ago,the man was 6 times as old as his son. \n" ); document.write( "M - 10 = 6(S - 10) \n" ); document.write( "Replace 'M' on right with 55 - S \n" ); document.write( "55 - S - 10 = 6S - 60 \n" ); document.write( "Collect like terms \n" ); document.write( "-S -6S = -60 + 10 - 55 \n" ); document.write( "-7S = -105 \n" ); document.write( " S = 15 \n" ); document.write( "Present ages. \n" ); document.write( "Son: 15yrs old \n" ); document.write( "Man: 40yrs old \n" ); document.write( "Hope this helps. \n" ); document.write( ";-) \n" ); document.write( " |