document.write( "Question 776267: in a certain town, 40% of the people have brown hair, 25% have brown eyes,and 15% have both brown hair and brown eyes. a person is selected at a random from the town. if he has brown eyes, what is the probability that he does not have brown hair? \n" ); document.write( "
Algebra.Com's Answer #473488 by oscargut(2103)\"\" \"About 
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BE = Brown eyes
\n" ); document.write( "BH = Brown hair\r
\n" ); document.write( "\n" ); document.write( "We know:\r
\n" ); document.write( "\n" ); document.write( "P(BH)=0.4
\n" ); document.write( "P(BE)=0.25
\n" ); document.write( "P(BH and BE) = 0.15\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "We want to know: P(BH/BE)\r
\n" ); document.write( "\n" ); document.write( "P(BH/BE)= P(BH and BE)/P(BE) = 0.15/0.4 = 0.375\r
\n" ); document.write( "\n" ); document.write( "Answer: 0.375\r
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\n" ); document.write( "\n" ); document.write( "I can help you with more questions at: mthman@gmail.com\r
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