document.write( "Question 776241: John is now four times as old as James. In 5 years, John will be three times as old as James. Find their present ages. \n" ); document.write( "
Algebra.Com's Answer #473477 by Cromlix(4381)![]() ![]() You can put this solution on YOUR website! John is now four times as old as James. \n" ); document.write( "John's age = 4 x James' age \n" ); document.write( "Jo = 4Ja \n" ); document.write( "In 5 years, John will be three times as old as James. \n" ); document.write( "John + 5 = 3(James + 5) \n" ); document.write( "Jo + 5 = 3Ja + 15 \n" ); document.write( "Replace Jo with 4Ja from first equation \n" ); document.write( "4Ja + 5 = 3Ja + 15 \n" ); document.write( "Collect like terms. \n" ); document.write( "4Ja - 3Ja = 15 - 5 \n" ); document.write( "Ja = 10. \n" ); document.write( "Present ages: \n" ); document.write( "John is 40 years old \n" ); document.write( "James is 10 years old. \n" ); document.write( "Hope this helps. \n" ); document.write( ":-)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |