document.write( "Question 66701: Find two consecutive integers such that the sum of 2 times the first integer and 4 times second integer is 46.\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

Algebra.Com's Answer #47340 by Earlsdon(6294) $\"\"$ $\"About$

You can put this solution on YOUR website!
Try this!
\n" ); document.write( "Let n be the first integer, then n+1 is the next consecutive integer. From the problem description, you can write:
\n" ); document.write( " $\"2n+%2B+4%28n%2B1%29+=+46\"$ Simplify and solve for n.
\n" ); document.write( " $\"2n+%2B+4n+%2B+4+=+46\"$ Combine like-terms.
\n" ); document.write( " $\"6n+%2B+4+=+46\"$ Subtract 4 from each side.
\n" ); document.write( " $\"6n+=+42\"$ Divide both sides by 6.
\n" ); document.write( " $\"n+=+7\"$ This is the first integer.
\n" ); document.write( " $\"n%2B1+=+8\"$ This is the next consecutive integer.\r
\n" ); document.write( "\n" ); document.write( "Check:
\n" ); document.write( "2(7) + 4(8) = 14 + 32 = 46 OK!
\n" ); document.write( " \n" ); document.write( "

\n" );