document.write( "Question 776068: I am not sure how to set this word problem up in order to solve.\r
\n" ); document.write( "\n" ); document.write( "Tim and Judy mix two kinds of feed for pedigreed dogs. They wish to make 27 pounds of feed worth $0.46 per pound by mixing one kind worth $0.31 per pound with another worth $.077 per pound. How many pounds of the cheaper kind should they use in the mix? \n" ); document.write( "

Algebra.Com's Answer #473354 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
Let $\"+a+\"$ = pounds of 31 cents/pound feed needed
\n" ); document.write( "Let $\"+b+\"$ = pounds of 77 cents/pound feed needed
\n" ); document.write( "---------------
\n" ); document.write( "(1) $\"+a+%2B+b+=+27+\"$
\n" ); document.write( "(2) $\"+%28+31a+%2B+77b+%29+%2F+27+=+46+\"$ ( in terms of cents )
\n" ); document.write( "----------------------------
\n" ); document.write( "(2) $\"+31a+%2B+77b+=+1242+\"$
\n" ); document.write( "Multiply both sides of (1) by $\"+31+\"$
\n" ); document.write( "and subtract (1) from (2)
\n" ); document.write( "(2) $\"+31a+%2B+77b+=+1242+\"$
\n" ); document.write( "(1) $\"+-31a+-+31b+=+-837+\"$
\n" ); document.write( " $\"+46b+=+405+\"$
\n" ); document.write( " $\"+b+=+8.804+\"$
\n" ); document.write( "and
\n" ); document.write( "(1) $\"+a+%2B+b+=+27+\"$
\n" ); document.write( "(1) $\"+a+=+18.196+\"$
\n" ); document.write( "18.196 pounds of cheaper seed are needed
\n" ); document.write( "check:
\n" ); document.write( "(2) $\"+%28+31a+%2B+77b+%29+%2F+27+=+46+\"$
\n" ); document.write( "(2) $\"+%28+31%2A18.196+%2B+77%2A8.804+%29+%2F+27+=+46+\"$
\n" ); document.write( "(2) $\"+%28+564.076+%2B+677.908+%29+%2F+27+=+46+\"$
\n" ); document.write( "(2) $\"+1241.984+=+27%2A46+\"$
\n" ); document.write( "(2) $\"+1241.984+=+1242+\"$
\n" ); document.write( "close enough
\n" ); document.write( " \n" ); document.write( "

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