document.write( "Question 775977: Help with factoring I need to factor and then solve for x\r
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document.write( "(x+1)(2x+1)^3 -3(2x+1)^2 (x+1)=0\r
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document.write( "I know that factored it is:
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document.write( "2(x+1)(2x+1)(2x^2+2x-1)
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document.write( "And solved for x it is:
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document.write( "x=-1, x= -.5, x=(-sqrt(3)-1)/2)(about -1.366), x= (sqrt(3)-1)/2)(about .366)\r
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document.write( "But no matter how I work it I am unable to end up where I am supposed to be, please mkae steps as clear as possible, thank you. \n" );
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Algebra.Com's Answer #473280 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Help with factoring I need to factor and then solve for x \n" ); document.write( "(x+1)(2x+1)^3 -3(2x+1)^2 (x+1)=0 \n" ); document.write( "Factored it is: \n" ); document.write( "(x+1)(2x+1)^2[2x+1-3] = 0 \n" ); document.write( "2(x+1)(2x+1)^2*(x-1) = 0 \n" ); document.write( "And solved for x it is: \n" ); document.write( "x= -1, x= +1 , x = -1/2 with multiplicity two \n" ); document.write( "------ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "======= \n" ); document.write( " |