document.write( "Question 775974: I am not sure how to set this word problem up in order to solve.\r
\n" ); document.write( "\n" ); document.write( "A merchant has coffee worth $5 a pound that she wishes to mix with 9 pounds of coffee worth $3 a pound to get a mixture that can be sold for $2 a pound. How many pounds of $5 coffee should be mixed
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Algebra.Com's Answer #473279 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Let \"+x+\" = pounds of $5 coffee needed
\n" ); document.write( "\"+5x+\" = cost of the $5 coffee
\n" ); document.write( "\"+3%2A9+=+27+\" = cost of the $3 coffee
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\n" ); document.write( "\"+%28+5x+%2B+27+%29+%2F+%28+x+%2B+9+%29+=+2+\"
\n" ); document.write( "\"+5x+%2B+27+=+2%2A%28+x+%2B+9+%29+\"
\n" ); document.write( "\"+5x+%2B+27+=+2x+%2B+18+\"
\n" ); document.write( "\"+3x+=+-9+\"
\n" ); document.write( "\"+x+=+-3+\"
\n" ); document.write( "The negative answer tells me it can't be solved.
\n" ); document.write( "Logically, there is no way you can mix $5/pound
\n" ); document.write( "coffee with $3/pound coffee and end up with
\n" ); document.write( "$2/pound coffee
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\n" ); document.write( "The cost/pound of the final mixture has to be
\n" ); document.write( "somewhere between $3 and $5
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