document.write( "Question 775978: I need to prove that\r
\n" ); document.write( "\n" ); document.write( "((x+4)/(3x^2-7x))=(((1/x)+(4/x^2))/(3-(7/x)))\r
\n" ); document.write( "\n" ); document.write( "By showing the steps,\r
\n" ); document.write( "\n" ); document.write( "So far I have tried working from the right side of the equation to get to the left, and made it into a complex fraction and combined it, then multiplied the numerator by the denominators reciprocal in order to make it a normal fraction and ended up with ((1-x)(1-4)/(3-7)(x^2-x))
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Algebra.Com's Answer #473278 by tanjo3(60)\"\" \"About 
You can put this solution on YOUR website!
\"%28x%2B4%29%2F%283+x%5E2-7+x%29+=+%281%2Fx%2B4%2Fx%5E2%29%2F%283-7%2Fx%29\"
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\n" ); document.write( "Let's leave the left side as is and only deal with the right side:
\n" ); document.write( "\"%281%2Fx%2B4%2Fx%5E2%29%2F%283-7%2Fx%29\"
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\n" ); document.write( "For the numerator and denominator, find a common denominator:
\n" ); document.write( "\"%28x%2Fx%5E2%2B4%2Fx%5E2%29%2F%283+x%2Fx-7%2Fx%29\"
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\n" ); document.write( "We can rewrite it as:
\n" ); document.write( "\"%28%28x%2B4%29%2Fx%5E2%29%2F%28%283x-7%29%2Fx%29\"
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\n" ); document.write( "Division with fraction means taking the reciprocal of the second number and multiplying.
\n" ); document.write( "\"%28%28x%2B4%29%2Fx%5E2%29%28x%2F%283x-7%29%29\"
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\n" ); document.write( "Simplify.
\n" ); document.write( "\"%28x%2B4%29%2F%28x%283x-7%29%29\"
\n" ); document.write( "\"%28x%2B4%29%2F%283+x%5E2-7+x%29%29\"
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\n" ); document.write( "Now we can see that the right side is equal to the left side.
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