document.write( "Question 775977: Help with factoring I need to factor and then solve for x\r
\n" ); document.write( "\n" ); document.write( "(x+1)(2x+1)^3 -3(2x+1)^2 (x+1)=0\r
\n" ); document.write( "\n" ); document.write( "I know that factored it is:
\n" ); document.write( "2(x+1)(2x+1)(2x^2+2x-1)
\n" ); document.write( "And solved for x it is:
\n" ); document.write( "x=-1, x= -.5, x=(-sqrt(3)-1)/2)(about -1.366), x= (sqrt(3)-1)/2)(about .366)\r
\n" ); document.write( "\n" ); document.write( "But no matter how I work it I am unable to end up where I am supposed to be, please mkae steps as clear as possible, thank you.
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Algebra.Com's Answer #473277 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "\"%28x%2B1%29%282x%2B1%29%5E3+-3%282x%2B1%29%5E2+%28x%2B1%29=0\"..factor out \"%28x%2B1%29%282x%2B1%29%5E2\"\r
\n" ); document.write( "\n" ); document.write( "\"%28x%2B1%29%282x%2B1%29%5E2%28%282x%2B1%29+-3%29=0\"\r
\n" ); document.write( "\n" ); document.write( "\"%28x%2B1%29%282x%2B1%29%5E2%282x%2B1+-3%29=0\"\r
\n" ); document.write( "\n" ); document.write( "\"%28x%2B1%29%282x%2B1%29%5E2%282x-2%29=0\"\r
\n" ); document.write( "\n" ); document.write( "\"%28x%2B1%29%282x%2B1%29%5E2%2A2%28x-1%29=0\"\r
\n" ); document.write( "\n" ); document.write( "\"2%28x%2B1%29%282x%2B1%29%282x%2B1%29%28x-1%29=0\"..use zero product rule to find solutions\r
\n" ); document.write( "\n" ); document.write( "if \"%28x%2B1%29=0\" => \"x=-1\"\r
\n" ); document.write( "\n" ); document.write( "if \"%282x%2B1%29=0\"=> \"2x=-1\"=>\"x=-1%2F2\"...this solution doubles\r
\n" ); document.write( "\n" ); document.write( "if \"%28x-1%29=0\"=> \"x=1\"\r
\n" ); document.write( "\n" ); document.write( "so, here you have three possible real solutions\r
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