document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=66699>Question 66699</A>: <I><SPAN STYLE=\"word-break: break-all;\"> What is wrong with this arguement? Suppose x and y represent two real numbers, where x > y\r<BR>\n" );
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document.write( "2 > 1<BR>\n" );
document.write( "2(y-x)> 1(y-x)<BR>\n" );
document.write( "2y-2x>y-x<BR>\n" );
document.write( "y-2x>-x<BR>\n" );
document.write( "y>x\r<BR>\n" );
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document.write( "The final inequality, y>x, is impossible because we were initally given x>y.\r<BR>\n" );
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document.write( "Extra info in problem possibly the \"arguement\"...This is a true statement . Multiply both sides by y-x. Use the distribtive property . Subtract from both sides. Add 2x to both sides.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #47327 by </B><A HREF=/tutors/aboutme.mpl?userid=Nate><B>Nate(3500)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Nate><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=47327\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A smaller number (y) minus a larger number (x) is a negative number ....<BR>\n" );
document.write( "so: y - x is a negative number<BR>\n" );
document.write( "2(y - x) > 1(y - x)<BR>\n" );
document.write( "2(a negative number) > 1(a negative number)<BR>\n" );
document.write( "2y - 2x < y - x<BR>\n" );
document.write( "y - 2x < -x<BR>\n" );
document.write( "y < x </SPAN>\n" );
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