document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=775915>Question 775915</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If f(x) = 2x+1 and m(x) = 3x-2, solve for x:  f(2x-1) - m(x+1)<BR>\n" );
document.write( "                                                                    _____________= 1<BR>\n" );
document.write( "                                                                    F(x) + 2m(x) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #473246 by </B><A HREF=/tutors/aboutme.mpl?userid=oscargut><B>oscargut(2103)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=oscargut><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=oscargut><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=473246\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If f(x) = 2x+1 and m(x) = 3x-2\r<BR>\n" );
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document.write( "f(2x-1) - m(x+1) =  2(2x-1)+1-(3(x+1)-2)= 4x-2+1-(3x+1) = x-2\r<BR>\n" );
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document.write( "f(x) + 2m(x) = 2x+1+2(3x-2) = 8x-3\r<BR>\n" );
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document.write( "Then :  (x-2)/(8x-3) = 1\r<BR>\n" );
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document.write( "x-2 = 8x-3\r<BR>\n" );
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document.write( "-7x = -1\r<BR>\n" );
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document.write( "x = 1/7\r<BR>\n" );
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document.write( "Answer: x = 1/7\r<BR>\n" );
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document.write( "I can help you with more questions at: mthman@gmail.com\r<BR>\n" );
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document.write( "Thanks </SPAN>\n" );
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