document.write( "Question 775854: X was twice as old as Y 10 years back. how old is Y if X will be 45 years old 15 years hence ? \n" ); document.write( "
Algebra.Com's Answer #473216 by MathTherapy(10552)\"\" \"About 
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\n" ); document.write( "X was twice as old as Y 10 years back. how old is Y if X will be 45 years old 15 years hence ?\r
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\n" ); document.write( "\n" ); document.write( "Let x’s current age be x, and y’s, y
\n" ); document.write( "Then 10 years ago, x was x – 10, and y was y – 10
\n" ); document.write( "Therefore, x – 10 = 2(y – 10), or x – 2y = - 10 ---- eq (i)\r
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\n" ); document.write( "\n" ); document.write( "Since 15 years from now, x will be 45, then x is now 30 (45 - 15)
\n" ); document.write( "30 – 2y = - 10 ------ Substituting 30 for x in eq (i)
\n" ); document.write( "– 2y = - 10 – 30
\n" ); document.write( "- 2y = - 40\r
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\n" ); document.write( "\n" ); document.write( "Y is currently \"%28-+40%29%2F-+2\", or \"highlight_green%2820%29\" years-old\r
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\n" ); document.write( "\n" ); document.write( "You can do the check!! \r
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\n" ); document.write( "\n" ); document.write( "Further help is available, online or in-person, for a fee, obviously. Send comments, “thank-yous,” and inquiries to “D” at MathMadEzy@aol.com
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