document.write( "Question 775854: X was twice as old as Y 10 years back. how old is Y if X will be 45 years old 15 years hence ? \n" ); document.write( "
Algebra.Com's Answer #473216 by MathTherapy(10552)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "X was twice as old as Y 10 years back. how old is Y if X will be 45 years old 15 years hence ?\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Let xs current age be x, and ys, y \n" ); document.write( "Then 10 years ago, x was x 10, and y was y 10 \n" ); document.write( "Therefore, x 10 = 2(y 10), or x 2y = - 10 ---- eq (i)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Since 15 years from now, x will be 45, then x is now 30 (45 - 15) \n" ); document.write( "30 2y = - 10 ------ Substituting 30 for x in eq (i) \n" ); document.write( " 2y = - 10 30 \n" ); document.write( "- 2y = - 40\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Y is currently \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "You can do the check!! \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Further help is available, online or in-person, for a fee, obviously. Send comments, thank-yous, and inquiries to D at MathMadEzy@aol.com \n" ); document.write( " |