document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=775856>Question 775856</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A group of men can do a job in as many days as there are men in the group. If the number of men is increased by 10, the number of days to do the job will be decreased by 8. Find the number of men in the group. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #473212 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=473212\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let the number of men be x\r<BR>\n" );
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document.write( "No of days taken = x\r<BR>\n" );
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document.write( "x men will do 1/x of the job in 1 day\r<BR>\n" );
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document.write( "x+10 men\r<BR>\n" );
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document.write( "number of days = x-8\r<BR>\n" );
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document.write( "(x-8)/(x-10)  of the job in 1 day\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28x-8%29%2F%28x%2B10%29+=+1%2Fx ALIGN=MIDDLE  ALT=\"%28x-8%29%2F%28x%2B10%29+=+1%2Fx\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "x^2-8x=x+10\r<BR>\n" );
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document.write( "x^2-9x-10=0\r<BR>\n" );
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document.write( "x^2-10x+x-10=0<BR>\n" );
document.write( "x(x-10)+1(x-10)=0\r<BR>\n" );
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document.write( "(x-10)(x+1)=0\r<BR>\n" );
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document.write( "x=10 OR -1<BR>\n" );
document.write( "ignore negative\r<BR>\n" );
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document.write( "x=10====> number of men\r<BR>\n" );
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document.write( "m.ananth@hotmail.ca </SPAN>\n" );
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