document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=775819>Question 775819</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hello! This is a very difficult question for me, considering the wording confuses me. Your help is greatly needed! And I would glady appreciate any help!\r<BR>\n" );
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document.write( "Question:\r<BR>\n" );
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document.write( "Jane can sail upstream in a river at an average rate of 4 miles per hour, and downstream at an average rate of 6 miles per hour. If she starts at 10:00 A.M, within what period of time must she turn around if she is to return to her point of depature between 6:00 P.M and 8:00 P.M?\r<BR>\n" );
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document.write( "Again I would really appreciate anyone that could help me! Thanks! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #473189 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=473189\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Jane can sail upstream in a river at an average rate of 4 miles per hour, and downstream at an average rate of 6 miles per hour. If she starts at 10:00 A.M, within what period of time must she turn around if she is to return to her point of depature between 6:00 P.M and 8:00 P.M?\r<BR>\n" );
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document.write( "let the distance she has to go one way be x\r<BR>\n" );
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document.write( "time upstream = x/4\r<BR>\n" );
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document.write( "time downstream = x/6\r<BR>\n" );
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document.write( "Total time should be less than 10 hours or greater than 8 hours\r<BR>\n" );
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document.write( "8<<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%2F4+%2Bx%2F6%7D%7D%3C10 ALIGN=MIDDLE  ALT=\"x%2F4+%2Bx%2F6%7D%7D%3C10\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "8<<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=5x%2F12%7D%7D%3C10 ALIGN=MIDDLE  ALT=\"5x%2F12%7D%7D%3C10\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "multiply by 12\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=96%3C5x%3C120 ALIGN=MIDDLE  ALT=\"96%3C5x%3C120\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "/5<BR>\n" );
document.write( "19.2 <x<24\r<BR>\n" );
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document.write( "She should return after 19.2 miles or before 24 miles\r<BR>\n" );
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document.write( "speed upstream is 4 mph\r<BR>\n" );
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document.write( "Earliest time to turn = 19.2/4 = 4.8 hours after starting ( 4 hours 48 min)\r<BR>\n" );
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document.write( "Latest time to turn 24/4 = 6 hours\r<BR>\n" );
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document.write( "She should turn after 2.48 pm\r<BR>\n" );
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document.write( "OR<BR>\n" );
document.write( "She should turn before 4.00 pm\r<BR>\n" );
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document.write( "m.ananth@hotmail.ca\r<BR>\n" );
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document.write( " </SPAN>\n" );
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