document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=775819>Question 775819</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hello! This is a very difficult question for me, considering the wording confuses me. Your help is greatly needed! And I would glady appreciate any help!\r<BR>\n" );
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document.write( "Question:\r<BR>\n" );
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document.write( "Jane can sail upstream in a river at an average rate of 4 miles per hour, and downstream at an average rate of 6 miles per hour. If she starts at 10:00 A.M, within what period of time must she turn around if she is to return to her point of depature between 6:00 P.M and 8:00 P.M?\r<BR>\n" );
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document.write( "Again I would really appreciate anyone that could help me! Thanks! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #473188 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=473188\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Jane can sail upstream in a river at an average rate of 4 miles per hour, and downstream at an average rate of 6 miles per hour. If she starts at 10:00 A.M, within what period of time must she turn around if she is to return to her point of depature between 6:00 P.M and 8:00 P.M?<BR>\n" );
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document.write( "Find the avg speed of a round-trip.<BR>\n" );
document.write( "It's 2*4*6/(4+6) = 4.8 mi/hr regardless of the distance.<BR>\n" );
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document.write( "From 10 to 6 = 8 hours --> RT distance = 38.4 miles, 19.2 miles each way.<BR>\n" );
document.write( "19.2 mi/4 mi/hr = 4.8 hours = 4:48<BR>\n" );
document.write( "1000 + 4:48 = 1448<BR>\n" );
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document.write( "From 10 to 8 = 10 hours --> RT distance = 48 miles, 24 miles each way.<BR>\n" );
document.write( "24 mi/4 mi/hr = 6 hours<BR>\n" );
document.write( "1000 + 6 = 1600<BR>\n" );
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document.write( "She has to turnaround between 1448 and 1600, or 2:48 and 4:00<BR>\n" );
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