document.write( "Question 775827: 4a+(3b-c) a=1/2 b=3/4 c=1/4 \n" ); document.write( "
Algebra.Com's Answer #473187 by tanjo3(60)\"\" \"About 
You can put this solution on YOUR website!
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Solved by pluggable solver: SUBSTITUTION solver -- compute expression given values
Your Result:

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  • Graphical form: \"4a%2B%283b-c%29\" simplifies to \"4\"
  • Text form: 4a+(3b-c) simplifies to 4
  • Cartoon (animation) form: \"simplify_cartoon%28+4a%2B%283b-c%29+%29\"
    For tutors: simplify_cartoon( 4a+(3b-c) )
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  • If you have a website, here's a link to this solution.
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DETAILED EXPLANATION

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Look at \"4%2Aa%2Bhighlight_red%28+%283%2Ab-c%29+%29\".
Remove unneeded parentheses around terms \"highlight_red%28+3%2Ab+%29\",\"highlight_red%28+-c+%29\"
It becomes \"4%2Aa%2Bhighlight_green%28+3%2Ab+%29-highlight_green%28+c+%29\".
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Look at \"4%2Ahighlight_red%28+a+%29%2B3%2Ab-c\".
Replaced a with 0.5
It becomes \"4%2Ahighlight_green%28+0.5+%29%2B3%2Ab-c\".
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Look at \"4%2A0.5%2B3%2Ahighlight_red%28+b+%29-c\".
Replaced b with 0.75
It becomes \"4%2A0.5%2B3%2Ahighlight_green%28+0.75+%29-c\".
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Look at \"4%2A0.5%2B3%2A0.75-highlight_red%28+c+%29\".
Replaced c with 0.25
It becomes \"4%2A0.5%2B3%2A0.75-highlight_green%28+0.25+%29\".
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Look at \"highlight_red%28+4%2A0.5+%29%2Bhighlight_red%28+3%2A0.75+%29-highlight_red%28+0.25+%29\".
Replace constants in expression: \"highlight_red%28+4%2A0.5+%29\",\"highlight_red%28+3%2A0.75+%29\",\"highlight_red%28+-0.25+%29\" with \"highlight_green%28+4+%29\"
It becomes \"highlight_green%28+4+%29\".
Result: \"4\"
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Universal Simplifier and Solver

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Done!
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