document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=775828>Question 775828</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A father is 41 years old and his son is 9. In how many years will the father be three times as old as his son? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #473186 by </B><A HREF=/tutors/aboutme.mpl?userid=tanjo3><B>tanjo3(60)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=tanjo3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=473186\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let n be the number of years until the stated condition is met, then:<BR>\n" );
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document.write( "41 + n = 3(9 + n)<BR>\n" );
document.write( "41 + n = 27 + 3n<BR>\n" );
document.write( "14 = 2n<BR>\n" );
document.write( "7 = n<BR>\n" );
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document.write( "In 7 years, the father will be three times as old as his son (he will be 48 and his son will be 16). </SPAN>\n" );
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