document.write( "Question 66663: The length of one of the equal legs of an isosceles triangle is 8 cm less than 4 times the length of the base. If the perimeter is 29 cm, find the length of one of the equal legs. \n" ); document.write( "
Algebra.Com's Answer #47314 by checkley71(8403)\"\" \"About 
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THE PERIMETER IS =B+L1+L2 L1 & L2 = 4B-8 THUS
\n" ); document.write( "B+4B-8+48-8=29
\n" ); document.write( "9B=29+16
\n" ); document.write( "9B=45
\n" ); document.write( "B=45/9
\n" ); document.write( "B=5 FOR THE BASE THUS THE SIDE IS
\n" ); document.write( "4*5-8=20-8=12
\n" ); document.write( "PROOF
\n" ); document.write( "5+12+12=29
\n" ); document.write( "29=29
\n" ); document.write( "
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