document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=775735>Question 775735</A>: <I><SPAN STYLE=\"word-break: break-all;\"> (16-5i)(-2 - i) with work shown? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #473108 by </B><A HREF=/tutors/aboutme.mpl?userid=swincher4391><B>swincher4391(1107)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=swincher4391><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=swincher4391><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=473108\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> This is a simple case of foiling, but you have to remember that i^2 = -1.\r<BR>\n" );
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document.write( "(16-5i)(-2-i)\r<BR>\n" );
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document.write( "first :  -32\r<BR>\n" );
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document.write( "outer: -16i\r<BR>\n" );
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document.write( "inner: 10i\r<BR>\n" );
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document.write( "last: 5i^2\r<BR>\n" );
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document.write( "-32 + -16i + 10i + 5i^2\r<BR>\n" );
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document.write( "-32 - 16i + 10i - 5\r<BR>\n" );
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document.write( "-6i - 37 </SPAN>\n" );
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