document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=775695>Question 775695</A>: <I><SPAN STYLE=\"word-break: break-all;\"> after A has traveled 2.5 hrs at the rate of 4.5 miles per hour, B starts to overtake him. if B travels 7 miles per hour, how far will they have traveled when B overtakes A? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #473092 by </B><A HREF=/tutors/aboutme.mpl?userid=psbhowmick><B>psbhowmick(878)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=psbhowmick><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=psbhowmick><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=473092\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Suppose B walks for T hours before overtaking A.<BR>\n" );
document.write( "Thus in T hours, the distance travelled by B = 7T miles.\r<BR>\n" );
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document.write( "By this time the total distance travelled by A would be = the distance already covered when B started + the distance covered in T hours = 2.5x4.5 + 4.5T\r<BR>\n" );
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document.write( "Since at time T B overtakes A so the total distance travelled by them at that point of time should be equal.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=7T+=+2.5%2A4.5%2B4.5T ALIGN=MIDDLE  ALT=\"7T+=+2.5%2A4.5%2B4.5T\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2.5T+=+2.5%2A4.5 ALIGN=MIDDLE  ALT=\"2.5T+=+2.5%2A4.5\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=T=4.5 ALIGN=MIDDLE  ALT=\"T=4.5\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "So the total distance covered by both A and B at the time T is 7 x 4.5 = 31.5 miles. </SPAN>\n" );
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