document.write( "Question 775702: find an equation in standard form for the perpendicular bisector of the segment joining (0,3) and (-4,5). \n" ); document.write( "

Algebra.Com's Answer #473088 by psbhowmick(878) $\"\"$ $\"About$

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Coordinates of the mid point of the line segment formed by joining the points ( $\"0\"$ , $\"3\"$ ) and ( $\"-4\"$ , $\"5\"$ ) is ( $\"%280-4%29%2F2\"$ , $\"%283%2B5%29%2F2\"$ ) i.e. ( $\"-2\"$ , $\"4\"$ )\r
\n" ); document.write( "\n" ); document.write( "Also, the slope of the line joining ( $\"0\"$ , $\"3\"$ ) and ( $\"-4\"$ , $\"5\"$ ) is $\"%285-3%29%2F%28-4-0%29=-1%2F2\"$ \r
\n" ); document.write( "\n" ); document.write( "Therefore the slope of the perpendicular is $\"2\"$ and it passes through the point ( $\"-2\"$ , $\"4\"$ ).\r
\n" ); document.write( "\n" ); document.write( "Therefore its equation is:
\n" ); document.write( " $\"y+-+4+=+2%28x+%2B+2%29\"$
\n" ); document.write( " $\"y+=+2x+%2B+8\"$ \n" ); document.write( "

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