document.write( "Question 775679: At a certain rate of simple interest, 500 Euros will accumulate to 600 Euros after a certain period of time. Find the accumulated value of Euros at a rate of simple interest one fourth as great over twice as long a period of time.
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Algebra.Com's Answer #473057 by psbhowmick(878)\"\" \"About 
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Let the rate of interest be R % per year and time period be T years.
\n" ); document.write( "Therefore, the first scenario can be represented by the equation
\n" ); document.write( "\"600+=+500%281+%2B+R%2AT%29\"
\n" ); document.write( "\"100+=+500RT\"
\n" ); document.write( "\"RT+=+1%2F5\" ________ (i)\r
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\n" ); document.write( "\n" ); document.write( "If the rate of interest is one fourth more than the existing rate then it becomes \"R+%2B+R%2F4+=+5R%2F4\"% and double the previous time period is \"2T\" years.\r
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\n" ); document.write( "\n" ); document.write( "With this new set of rate of interest and time period, the accumulated value A would be:
\n" ); document.write( "\"A+=+500%281+%2B+%285%2AR%2F4%29%2A2T%29\"
\n" ); document.write( "\"A+=+500%281+%2B+%285%2F2%29%2ART%29\"
\n" ); document.write( "\"A+=+500%281+%2B+%285%2F2%29%2A%281%2F5%29%29\" [substituting value of \"RT\" from (i)]
\n" ); document.write( "\"A+=+500%281+%2B+1%2F2%29=500%2A%283%2F2%29=750\"\r
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\n" ); document.write( "\n" ); document.write( "Hence, the accumulated value would be 750 Euros
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