document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=775601>Question 775601</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Write an equation of the line that passes through (1,-1) and is perpendicular to the line y= -1/2x+6.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #473044 by </B><A HREF=/tutors/aboutme.mpl?userid=Cromlix><B>Cromlix(4381)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Cromlix><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Cromlix><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=473044\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Lines that are perpendicular to one<BR>\n" );
document.write( "another have slopes (m) that multiply<BR>\n" );
document.write( "to give -1<BR>\n" );
document.write( "y = -1/2x + 6<BR>\n" );
document.write( "Has a slope (m) of -1/2<BR>\n" );
document.write( "So, the line that is perpendicular<BR>\n" );
document.write( "to it has a slope of 2<BR>\n" );
document.write( "-1/2 * 2 = -1<BR>\n" );
document.write( "Using y - b = m(x - a) with (1,-1)<BR>\n" );
document.write( "with a = 1, b = -1 and m = 2<BR>\n" );
document.write( "y - (-1) = 2(x - 1)<BR>\n" );
document.write( "y + 1 = 2x - 2<BR>\n" );
document.write( "y = 2x - 2 - 1<BR>\n" );
document.write( "y = 2x - 3<BR>\n" );
document.write( "Hope this helps.<BR>\n" );
document.write( ":-) </SPAN>\n" );
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