document.write( "Question 775609: If a boy walks from his house to school at 4 km/h, he reaches the school 10 minutes earlier than the scheduled time. However if he walks the rate of 3 km/h he reaches 10 minutes late. The distance of the school from his house is \n" ); document.write( "
Algebra.Com's Answer #473014 by josmiceli(19441)![]() ![]() You can put this solution on YOUR website! Let \n" ); document.write( "if he is to arrive at the scheduled time \n" ); document.write( "Let \n" ); document.write( "-------------- \n" ); document.write( "Equation for leaving early: \n" ); document.write( " \n" ); document.write( "--------------------- \n" ); document.write( "Equation for leaving late: \n" ); document.write( " \n" ); document.write( "--------------------- \n" ); document.write( "By substitution: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Multiply both sides by \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "----------- \n" ); document.write( "By substitution: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "The distance of the school from his house is 4 km \n" ); document.write( "------------ \n" ); document.write( "check: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "OK \n" ); document.write( " \n" ); document.write( " |